Getting Id of selected row on clicking delete button.

Title:

BI{code} ?

Hi! I have bound my grid to a js function for getting data. my js function is providing data which is present in a js object array, every array element have Id property, as the grid is not backed by a model but a js array, every row has delete button, as grid does not have a model on back so how do I get Id of selected row on clicking delete button? This function is providing data to grid: function getTypeGridData(gp) { var g = utils.getGridParams(gp); function map(o) { return { Id: o.Id, Name: o.Name, TypeName: o.TypeName, Description: o.Description, IsDeleted : o.IsDeleted }; }; return utils.gridModelBuilder(this, g, typesList, { key: "Id", map: map }); } and grid is like : @(Html.Awe().Grid("TypeGrid") .DataFunc("getTypeGridData") .Sortable(true) .Mod("loadingGrid") .Columns( new Column { ClientFormat = ".Id", Hidden = true }, new Column { Header = "Name", Name = "Name" Sort = Omu.AwesomeMvc.Sort.Asc }, new Column { Header = "Delete", ClientFormatFunc = "utils.deleteFormat('deleteTypeGrid','TypeGrid')"})) As utils.deleteFormat always get the model of row but here model is not present, just a js array which is providing data , so how do I implement delete function for a row?? or how to get Id from row when click delete.

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Sam Mosaic

asked at 18 Sep 2019

Answers

• BI{code} ?

  ok, so the grid row model is the one you defined in `map`, so if you set ClientFormatFuc = "myfunc" and having: function myfunc(model){ console.log(model); // you'll see here the model with all the properties // so you could return return '<button type="button" onclick="myDeleteFunc(\'' + model.Id + '\')">delete</button>'; } of course you could also use `ClientFormat`, more examples here: https://demo.aspnetawesome.com/GridDemo/CustomFormat

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  Omu

  answered at 18 Sep 2019

  • Thanks a lot.. You saved my hours.
    at 18 Sep 2019 Sam Mosaic

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