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PopupForm submit after failed submit
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I
{code}
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Hi, after a "failed submit" the Save button is ineffective. What I mean with "failed submit" is, a validation failure happens inside my server and a failure message would be returned to the client and displayed (see below - Error handling). PopupForm: function ShowPopup() { @Url.Awe().PopupFormAction().Name("DataEntry").Url(Url.Action("Create", "DataEntry")).ParameterFunc("CreateParameters").Height(600).Width(820).Modal(false).OkText("Save").CancelText("Cancel").Resizable(true); } ErroHandling: $.ajaxSetup({ error: function (XMLHttpRequest, textStatus, errorThrown) { alert("Error: " + textStatus + ": " + errorThrown); } }); How could I change this? I wanna click at the Save Button again, even though a failure happens before. Thanks in advance, Christoph
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PDMDSUI
asked at 11 Mar 2014
this happens for an unhandled exception, you can put a try catch in the post action and handle the exception
at 11 Mar 2014
Omu
OK thanks. My solution: - Added a try catch block, handle the exception and return a failure message as json object. - Prevent dialog to close on success .CloseOnSuccess(false) - Handle the response in a success method .Success("OnSuccess") ... function OnSuccess(e) { if (e.success) {$("#DataEntry").dialog("close");} else {alert(e.error);} };
at 12 Mar 2014
PDMDSUI
you can also add it as a model error ModelState.AddModelError(string key, string errorMessage); http://stackoverflow.com/a/5740852/112100
at 12 Mar 2014
Omu
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